From 119687ab933828f359372927ca7d5129cb108d0b Mon Sep 17 00:00:00 2001
From: Holden Rohrer <hr@hrhr.dev>
Date: Tue, 15 Sep 2020 14:30:01 -0400
Subject: ugh harsh grading scheme

---
 GRADES         | 1 +
 houdre/hw1.tex | 5 +++++
 2 files changed, 6 insertions(+)

diff --git a/GRADES b/GRADES
index ca55755..8cdd37a 100644
--- a/GRADES
+++ b/GRADES
@@ -18,3 +18,4 @@ Reading quiz one: 10/10     =100%
 
         Houdre
         ------
+Homework One: 38/50         = 76%
diff --git a/houdre/hw1.tex b/houdre/hw1.tex
index 4baddda..c06f5fa 100644
--- a/houdre/hw1.tex
+++ b/houdre/hw1.tex
@@ -136,6 +136,8 @@ These are both calculated using inclusion-exclusion, the first being
 three independent events with probabilities $(p^2,p^2,p)$ and the second
 being several dependent probabilities.
 
+% Insufficient explanation (6/10)
+
 \q14
 
 $$\Pr(A\cup B) = \Pr(A\setminus B)+\Pr(B\setminus A)+\Pr(A\cap B)$$
@@ -247,4 +249,7 @@ $$= 3\Pr(\hbox{matched red}) = 3{6\over(3+n)(2+n)}
 This means that the probability of matched black socks is the same as
 the probability of matched red socks: ${6\over(3+3)(2+3)} = {1\over5}$.
 
+% This is mostly correct, but n is actually the total number of socks,
+% so n=6. 2/10
+
 \bye
-- 
cgit