From 54ca67bc4b75fe2ad6d2f68aa4eff61f781d2af8 Mon Sep 17 00:00:00 2001
From: Holden Rohrer <hr@hrhr.dev>
Date: Mon, 1 Nov 2021 16:18:06 -0400
Subject: updates for math and physics homeworks

---
 jarrio/week9practice.bc | 162 ------------------------------------------------
 1 file changed, 162 deletions(-)
 delete mode 100644 jarrio/week9practice.bc

(limited to 'jarrio/week9practice.bc')

diff --git a/jarrio/week9practice.bc b/jarrio/week9practice.bc
deleted file mode 100644
index 611dc8e..0000000
--- a/jarrio/week9practice.bc
+++ /dev/null
@@ -1,162 +0,0 @@
-########################################################################
-print "Weekly Homework 9\n"
-pi = 4*a(1)
-epsilon = 8.85 * 10^(-12)
-epercoul = 6.24 * 10^18
-# Conductivity constants ( resistitvity = 1/sigma)
-sigmairon = 1*10^7
-sigmacopper = 6*10^7
-sigmasilver = 6.2*10^7
-sigmagold = 4.1*10^7
-sigmaaluminum = 3.5*10^7
-sigmatungsten = 1.8*10^7
-sigmanichrome = 6.7*10^5
-sigmacarbon = 2.9*10^4
-
-print "Question 1\n"
-#params
-i = 1.9/1000 # A
-diam = 5/1000 # m
-
-r = diam/2
-"Protons Per Second "
-i*epercoul
-# i = \int_0^R J_edge (r/R) 2\pi r dr
-#   = J_edge/R [ 2\pi r^3 / 3 ]_0^R
-#   = 2\pi J_edge R^2/3
-jedge = 3*i/(2*pi*r^2)
-"J_edge (A/m^2) "
-jedge
-
-print "Question 2\n"
-# Equilibrium: eta/2epsilon + EF_I2 = EF_I1
-# EF_I = V/L = IR/L = I(L/sigma/A)/L = I/(sigma*A)
-# eta = 2epsilon * ( I/(sigma1*A)-I/(sigma2*A) )
-# Corrections from pearson: apparently it should be eta/epsilon, and the
-# sign was opposite, so correct is
-print "eta = epsilon * ( I/(sigma2*A)-I/(sigma1*A))\n"
-#params
-diam = 1/1000 # m
-i = 3 # A
-
-a = pi*r^2 # m^2
-r = diam/2 # m
-"Charge on the boundary "
-# eta * a
-epsilon * i * (1/(sigmairon*a) - 1/(sigmacopper*a)) * a
-
-print "Question 3\n"
-#params
-diam = .5 # mm
-i = 20 # mA
-
-diam = diam/1000 # m
-r = diam/2 # m
-i = i/1000 # A
-
-a = pi*r^2
-j = i/a
-# j = ef*sigma
-ef = j/sigmasilver
-"Electric Field (V/m) "
-ef
-
-"Electron drift speed (m/s) " # idk lol
-ve = 5.8 * 10^28 # number/m^3
-ie = i*epercoul # number/s
-ie/a/ve
-
-print "Question 4\n"
-diam = 1 # mm
-diam = diam/1000 # m
-r = diam/2
-a = pi*r^2
-# efnichrome = efaluminum
-# jnichrome/sigmanichrome = jaluminum/sigmaaluminum
-# i/pi*(diam_nichrome/2)^2/sigmanichrome = i/a/sigmaaluminum
-# pi*(diam_nichrome/2)^2*sigmanichrome = a*sigmaaluminum
-"Diameter of nichrome (m) "
-2*sqrt(a*sigmaaluminum/sigmanichrome/pi)
-
-print "Question 5\n"
-#params
-l = 10 # cm
-innerdiam = 2.8 # mm
-outerdiam = 3   # mm
-v = 3 # V
-
-l = l/100 # m
-innerdiam = innerdiam/1000 # m
-innerr = innerdiam/2
-outerdiam = outerdiam/1000 # m
-outerr = outerdiam/2
-a = pi*outerr^2 - pi*innerr^2
-ef = v/l
-j = ef*sigmanichrome
-i = j*a
-"Current (A) "
-i
-
-print "Question 6\n"
-print "60W means higher resistance, so it has a higher voltage drop\n"
-print "and takes more energy\n"
-
-v = 120 # V
-w1 = 60 # W (wattage of lightbulb 1 @ 120V)
-# w1 = i*v = v*v/r1
-r1 = v^2/w1
-r1
-w2 = 100 # W
-r2 = v^2/w2
-i = v/(r1+r2)
-print "Power by the first bulb (W) "
-i^2*r1
-print "Power by the second bulb (W) "
-i^2*r2
-
-print "Question 7\n"
-#params
-r = 70 # Ohm
-
-v = 9 # V
-i = v/r
-
-"Magnitude of Current (A) "
-i
-
-print "Direction is left to right (positive to negative)\n"
-
-print "Question 8\n"
-#params
-w = 1100 # W
-
-v = 120 # V
-"Resistance (Ohm) "
-r = v^2/w
-r
-
-"Current (A) "
-v/r
-
-print "Question 9\n"
-#params
-m = 1 # g aluminum
-p = 8 # W
-v = 1.5 # V
-
-m = m/1000 # kg
-r = v^2/p # Ohm
-densityaluminum = 2.7 # g/cm^3
-densityaluminum = densityaluminum*1000 #kg/m^3
-vol = m/densityaluminum # m^3
-rhoaluminum = 1/sigmaaluminum # Ohm*m
-# R = rhoaluminum * l / A = rhoaluminum * l / (vol/l) =
-# rhoaluminum*l^2 / vol
-l = sqrt(r/rhoaluminum*vol) # m
-# Cross-sectional area
-a = vol/l # m^2
-"Diameter (mm) "
-2*sqrt(a/pi) * 1000
-
-"Length (m) "
-l
-- 
cgit