From 32f4af5f369fa9f0b2988ecad7797f4bec3661c3 Mon Sep 17 00:00:00 2001
From: Holden Rohrer <hr@hrhr.dev>
Date: Tue, 21 Sep 2021 17:12:46 -0400
Subject: notes and homework

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+    Linear Independence and Linear Span
+Solution set for Ax=0, Ax=B, and the dimension of null space/rank of a
+matrix.
+
+Def. linear independence over vector space (V, +, *)
+Let v = {v1, ..., vk} be vectors in V. We say v is linearly independent
+iff whenever a1v1 + a2v2 + ... akvk = 0, a1 = a2 = ... = ak = 0.
+
+Where v_i in v in R^n, we can find linear independence by writing it as
+
+[ v1 | v2 | ... | vk ][a1 a2 ... ak]^T = 0
+
+Prove: basis of a vector space has the same dimension regardless of the
+vectors.
+
+Def basis: a linearly independent set of vectors which spans a vector
+space.
-- 
cgit