From f71719631dd793f39e6c629314fd81a4c06c19d2 Mon Sep 17 00:00:00 2001 From: Holden Rohrer Date: Fri, 17 Jan 2020 00:32:53 -0500 Subject: finally made schedule.js --- architecture | 21 --------------------- 1 file changed, 21 deletions(-) delete mode 100644 architecture (limited to 'architecture') diff --git a/architecture b/architecture deleted file mode 100644 index c161699..0000000 --- a/architecture +++ /dev/null @@ -1,21 +0,0 @@ -Say you have several queues A, B, ... -Each queue has a length K_n. -Each queue has a weight K_w. K_w adjusted such that \sumK_w=1 -If k items are requested, a set of items from the tops of each relevant queue will be returned. -K_c <= K_n items were chosen from queue K. -Minimize \sum|kK_w-K_c|. << Jesus Christ that's it. How could I be so stupid. - -main(queueList, num) -> while (not have num) getNumOrAll(queueList[top], remaining) - -getNumOrAll(queue, num): - Step 1: Make array of num*job.weight - Step 2: "Remove" all num%1 from array, and count - Step 3: "Sort" array by num. - Step 4: Continue counting. Subtract one from each array member until at num. -^^ Not perfect - Step 1: (Pre-)sort by job.data.length/job.weight. - Step 2: Start at lowest, and pop all until job.data.length>job.normweight*num (decreasing num as popping and recalc job.normweight). - Step 2.5: If empty, remove prio && jobs[prio]; return. - Step 3: Then, pop job.normweight*num//1 elems from remaining, without num decrease or normweight recalc. But keep job.wacc = job.normweight*num%1 - Step 4: Shallow copy job array, and sort by job.wacc. - Step 5: Iterate through array (high->low), and subtract 1 until the length of output is num. -- cgit